u^2+76=180

Solution for u^2+76=180 equation:

u^2+76=180

We move all terms to the left:

u^2+76-(180)=0

We add all the numbers together, and all the variables

u^2-104=0

a = 1; b = 0; c = -104;
Δ = b2-4ac
Δ = 02-4·1·(-104)
Δ = 416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{416}=\sqrt{16*26}=\sqrt{16}*\sqrt{26}=4\sqrt{26}$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{26}}{2*1}=\frac{0-4\sqrt{26}}{2}
=-\frac{4\sqrt{26}}{2}
=-2\sqrt{26}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{26}}{2*1}=\frac{0+4\sqrt{26}}{2}
=\frac{4\sqrt{26}}{2}
=2\sqrt{26}
$